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what is the time periodof earth when omega is 1.2 * 10^ -3 rad per sec

Nikhil , 6 Years ago
Grade 11
anser 1 Answers
Aman

Last Activity: 6 Years ago

We know that time period = 2pi/w
Here w is angular vel. Omega.
Hence 6.28/1.2*10^-3=  5.2222*10^3.
Thanks

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