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What is the relation between angular accelaration and linear accelaration?
What is the relation between angular accelaration and linear accelaration?

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4 years ago

```							like linear speed
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4 years ago
```							linear speed=angular speed x radiusdifferentitate both sides we getlinear acceleration = angular acceleration x radiushappy to help u
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4 years ago
```							The relation is as followsLinear acceleration=radius×angular acceleration        Where radius is the radius in which the body  undergoes circular motionAll the best.
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4 years ago
```							@soumya by the defination of radian measure so, by that s = r theta taking a as derivative v = r omega and anathor a = r alpha the linear acceleration of that point is the vector sum of these two perpendicular componenet of the acceleration HOPE IT CLEARS ALL THE BEST ..
```
4 years ago
```							Angular acceleration= radius * linear acceleration BUT THIS IS VALID ONLY WHEN THE BODY PERFORMS PURE ROLLING
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3 years ago
```							Sorry for the above answerSlight mistake Linear acceleration = radius *angular acceleration BUT ONLY WHEN IT PERFORMS PURE ROLLING
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3 years ago
```							Angular acceleration:-Rate of change of angular velocity which further is the rate of change of the angle thita.Linear acceleration:-The tangential velocity in case of body moving with constant speed in a circle.
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3 years ago
```							Angular acceleration[α] actually equal to centripetal acceleration.angular acceleration is the rate of change of angular velocity which further is the rate of change of the angle(theta) this is very similar to how the linear acceleration is defined α=d2x/dt2α=d2(theta)/dt2Linear acceleration is F/mAngular acceleration is tau/Itau=Torque, I=moment of inertia(equivalent to mass) Tangential velocity (V) in case of a body moving with constant speed in a circle is same as its ordinary speed. Speed is along the tangent to the circle (path of motion for the body) the magnitude is equal to the rate at which it moves along the circle. Geometrically we can show thatV=rw
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3 years ago
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