What is the relation between angular accelaration and linear accelaration?

							like linear speed
						

							
linear speed=angular speed x radius
differentitate both sides we get
linear acceleration = angular acceleration x radius
happy to help u
						

							The relation is as followsLinear acceleration=radius×angular acceleration        Where radius is the radius in which the body  undergoes circular motionAll the best.
						

							
@soumya 
by the defination of radian measure 
so, by that s = r theta 
taking a as derivative 
v = r omega 
and anathor a = r alpha 
the linear acceleration of that point is the vector sum of these two perpendicular componenet of the acceleration 
HOPE IT CLEARS 
ALL THE BEST ..
						

							Angular acceleration= radius * linear acceleration BUT THIS IS VALID ONLY WHEN THE BODY PERFORMS PURE ROLLING
						

							Sorry for the above answerSlight mistake Linear acceleration = radius *angular acceleration BUT ONLY WHEN IT PERFORMS PURE ROLLING
						

							Angular acceleration:-Rate of change of angular velocity which further is the rate of change of the angle thita.Linear acceleration:-The tangential velocity in case of body moving with constant speed in a circle.
						

							Angular acceleration[α] actually equal to centripetal acceleration.angular acceleration is the rate of change of angular velocity which further is the rate of change of the angle(theta) this is very similar to how the linear acceleration is defined α=d2x/dt2α=d2(theta)/dt2Linear acceleration is F/mAngular acceleration is tau/Itau=Torque, I=moment of inertia(equivalent to mass) Tangential velocity (V) in case of a body moving with constant speed in a circle is same as its ordinary speed. Speed is along the tangent to the circle (path of motion for the body) the magnitude is equal to the rate at which it moves along the circle. Geometrically we can show thatV=rw