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Grade: 12
        
What is the change in surface energy when a drop of radius R split up into 1000 droplets of radius r ?
23 days ago

Answers : (1)

Arun
15947 Points
							
 

Volume of bigger drop = Total volume of 8 droplets

(4/3)*pi* R3   =  1000 (4/3)* pi* r3

=> r = R/10

Change in surface area in this process = ds = 4* pi * [10*R2 - R2] = 4* pi* 9R²

Hence work done = T.ds = T* 36*pi*R2

23 days ago
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