Grade 12Mechanics
What is the centre of mass of hemi hollow share .derive it`s formula
1 Answer
Vikas TU
Dear Student,
For small element dm,
For small element dm,
- dm= M/2πR2 x 2πRsinα Rdα
=Msinα dα
Yc= 1/Mꭍdmy
=1/M (from 0 to π/2)ꭍMsinαdαRcosα
=-R/2[cos2α/2] (from 0 to π/2)
=R/2.Cheers!!Regards,Vikas (B. Tech. 4th year
Thapar University)
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