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`        what is relation between height h and depth d for the change in g `
one year ago

```							At a height of h from the surface of the earth, the gravitational force on an object of mass m isF = GMm/(R+h)^2Here (R + h) is the distance between the object and the centre of earth.Say at that height h, the gravitational acceleration is g1.So we can write, mg1 = GMm / (R+h)^2=> g1 = GM/(R+h)^2 _________________ (5)Now we know on the surface of earth, it is g =  GM / R^2Taking ratio of these 2,g1/g = R^2 /(R+h)^2= 1/(1 + h/R)^2 = (1 + h/R)^(-2) = (1 – 2h/R)=> g1/g = (1 – 2h/R)=> g1 = g (1 – 2h/R) ___________________ (6)So as altitude h increases, the value of acceleration due to gravity falls.
```
one year ago
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