What is a reasonable estimate for the maximum number of objects a juggler can juggle with two hands if the height to which the objects are tossed above the hands is h?

Given that the object rises to height h above the hands, the time t can be calculated using equation (1) as:

Where g is the free fall acceleration 9.81 m /s².
The time (t’) for which the ball stays in the air is given by multiplying time t by 2, that is:

If the number of objects tossed per second by each hand is n then the number of objects (n’) tossed by both the hands in time t’ is:


Therefore one can see that the number of objects than can be tossed by both the hands depends on the height h and the number of rate at which the object can be tossed.