Water from a pipe of cross sectional area 10^-2 m^2 gushes out of the tube horizontal ly with a speed of 15m/sec .The water hits a vertical wall nearby and rebounds with the same speed What is the force exerted by the impact of water.
Paridhi Chawhan , 5 Years ago
Grade 11
1 Answers
Vikas TU
Last Activity: 5 Years ago
Cross sectional area = 10^-2 Spped = 15m/sec Vol of water coming out from pipe V = Av = 15 * 10^-2 Density of water = 10^3 kg/m^3 Mass of water flowing out through pipe = row*v = 150 kg /sec Force extended by water on wall =Rate of change of momentum = delP /del T = mv / t => 150*15 = 2250N
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free