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`        Water flows along a horizontal pipe whose cross section is not constant .the pressure is 1 cm Hg where the velocity is 35 cm/s .At a point where the velocity is 65 cm/s , the pressure will be ?`
2 years ago

Vikas TU
9510 Points
```							Bernouli’s eqn. would be still valid here.Therefore,Patm + pgh + 0.5pv^2 = Constant.Now,1g1 + 0.5*p35^2 = 1gh + 0.5p*65^2gh = 1*10*1 + 0.5*1*35^2 –  0.5*1*65^2gh = 1490 cmh = 149 cm Hg.
```
2 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions