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Water flows along a horizontal pipe whose cross section is not constant .the pressure is 1 cm Hg where the velocity is 35 cm/s .At a point where the velocity is 65 cm/s , the pressure will be ?

Sumit Jha , 9 Years ago
Grade 11
anser 1 Answers
Vikas TU
Bernouli’s eqn. would be still valid here.
Therefore,
Patm + pgh + 0.5pv^2 = Constant.
Now,
1g1 + 0.5*p35^2 = 1gh + 0.5p*65^2
gh = 1*10*1 + 0.5*1*35^2 –  0.5*1*65^2
gh = 1490 cm
h = 149 cm Hg.
  
Last Activity: 9 Years ago
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