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water drops fall at regular intervals from tap which is 5m above the ground.the third drop is leaving the tap at the istsant the first drop touches the ground.How far above the ground is the second drop at that instant??

Vaibhavi Kulkarni , 8 Years ago
Grade 9
anser 1 Answers
RAJ ARYAN
for the third droph=ut+1/2gt^2u=0.`.h=1/2gt^2 =>t=(2h/g)^1/2as there are 3 drops .`. time interval = [(2h/g)^1/2]/2=> 1/2 (2h/g)1^2as its the second drop.`. h=ut+1/2g [1/2 (2h/g)1^2]u=0 .`. putting values givesh=10/8 (when g=10)
Last Activity: 8 Years ago
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