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`        Water drops fall at regular intervals from a top which is 5 m above the ground. The third drop is leaving the tap at the instant the first drop touches the ground. How far above the ground is the second drop at that instant.`
one year ago

Venu Choudhary
10 Points
```							First u need to find the time of flight of 1st drop as:T=sqrt(2h/g)=1secThe time 1sec is divided in intervals for 3 drops as T/3..So when the 1st drop has travelled for T/3 seconds then the second drop leaves..Time of flight of 2nd drop when 1st drop reaches ground =T-T/3Height above ground=5-1/2*g*t*t where t= T-T/3
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions