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Velocity of a stone projected ,2 secondbeforeit reaches the maximum height ,make angle 53 degrees with the horizontal then the velocity at highest point will be\t20m/ss\t15m/s\t25m/s\t80/3 m/s

Riya Das , 5 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 5 Years ago

Dear student
 
 
Acc to ques, 2 seconds before it reaches the maximum height it makes an angle of 53 deg
=> Initial velocity of y-component will be (Uy)=Usin53
=> Initial velocity of x-component will be (Ux)=Ucos53
Therefore, Vy=Uy-gt
               =>0=Usin53-20
               =>U=25m/s
Now, At highest point the y-component velocity is 0, only x-comp velocity exists which remians constant throughout the projectile motion.
Hence, At highest point the overall velocity of stone will be equal to the x-component velocity
ie, Ucos53=25x3/5=15m/s ANSWER

Hope it helps
 
Regards
Arun

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