Grade 10Mechanics
vector a =icap+jcap-kcap.vector b =3jcap+5kcap angle between vector a and b is
vector a =icap+jcap-kcap.vector b =3jcap+5kcap angle between vector a and b is
1 Answer
Vikas TU
As we realize that
Vector a . vector b = |vector a| x |vector b| cosѳ
cosѳ = (Vector a . vector b)/( |vector a| x |vector b|)
=(( icap+jcap-kcap).( 3jcap+5kcap))/(√3x√34)
= - 2/√102
Ѳ = cos-1(- 2/√102)
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