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Use Eqs. 11-3 and 11 -5 to calculate the angle between the two vectors and
By using equation (1),a . b = (3 i + 3 j+ 3 k). (2 i + j+ 3 k) = (3×2) + (3×1) +(3×3) =6+3+9 =18 …… (3)By using equation (2),a . b = (5.19) (3.74) cos ?So, cos ? = a . b/(5.19) (3.74)Φ = cos [a . b/(5.19) (3.74)] …… (4)To find out the angle between a and b, substitute 18 for a . b in the equation (4) we get,Φ = cos [a . b/(5.19) (3.74)] = cos [18/(5.19) (3.74)] = 22.0° …… (5)From equation (5) we observed that, the angle between a and b will be 22.0°.
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