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two trains one of length 100m and another of length 125m are moving in mutually opposite directions along parallel lines, meet each other, each with speed 10m/s. if their acceleration are 0.3 m/s 2 and 0.2m/s 2 respectively then find the time taken to pass each other.
Length of first train = 100m.Length of second train = 125m.So, total crossing distance = 100+125 = 225m.Velocity of both train = 10m/s .acceleration of first train = 0.3m/s2.acceleration of second train = 0.2m/s2.Since both train moving to opposite direction of each other. so, velocity and acceleration is added to find the time taken to cross each other.so, velocity = 10+10 = 20m/s. acceleration = 0.3+0.2 = 0.5m/s.Now using kinemaics second equation. S = Ut +at2/2.225 = 20t +0.5t2/2. t2 +80t – 1000= 0.Now solving aove equation. t = 10.99s and -90.99s.negative value is not possible so t = 10.99 s.
Do the same as he has done but in the place of 1000 there will be 900.t^2+80t-900=0t^2+90t-10t-900=0t(t+90)-10(t+90)=0t=-90 and t=10.Here t=-90 is rejected so t=10 is the answer.
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