Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

two trains one of length 100m and another of length 125m are moving in mutually opposite directions along parallel lines, meet each other, each with speed 10m/s. if their acceleration are 0.3 m/s 2 and 0.2m/s 2 respectively then find the time taken to pass each other.

two trains one of length 100m and another of length 125m are moving in mutually opposite directions along parallel lines, meet each other, each with speed 10m/s. if their acceleration are 0.3 m/s2 and 0.2m/s2 respectively then find the time taken to pass each other.

Grade:11

2 Answers

Deepak Kumar
31 Points
3 years ago
Length of first train = 100m.
Length of second train = 125m.
So, total crossing distance = 100+125 = 225m.
Velocity of both train = 10m/s .
acceleration of first train = 0.3m/s2.
acceleration of second train = 0.2m/s2.
Since both train moving to opposite direction of each other.
 so, velocity and acceleration is added to find the time taken to cross each other.
so, velocity = 10+10 = 20m/s.
      acceleration = 0.3+0.2 = 0.5m/s.
Now using kinemaics second equation.
 S = Ut +at2/2.
225 = 20t +0.5t2/2.
  t+80t – 1000= 0.
Now solving aove equation.
  t = 10.99s and -90.99s.
negative value is not possible so t = 10.99 s.
 
Ajinkya
11 Points
3 years ago
Do the same as he has done but in the place of 1000 there will be 900.
t^2+80t-900=0
t^2+90t-10t-900=0
t(t+90)-10(t+90)=0
t=-90 and t=10.
Here t=-90 is rejected so t=10 is the answer.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free