Grade 11Mechanics

two trains one of length 100m and another of length 125m are moving in mutually opposite directions along parallel lines, meet each other, each with speed 10m/s. if their acceleration are 0.3 m/s² and 0.2m/s² respectively then find the time taken to pass each other.

Kaushal Jain

8 Years agoGrade 11

2 Answers

Deepak Kumar

8 Years ago

Length of first train = 100m.

Length of second train = 125m.

So, total crossing distance = 100+125 = 225m.

Velocity of both train = 10m/s .

acceleration of first train = 0.3m/s².

acceleration of second train = 0.2m/s².

Since both train moving to opposite direction of each other.

so, velocity and acceleration is added to find the time taken to cross each other.

so, velocity = 10+10 = 20m/s.

acceleration = 0.3+0.2 = 0.5m/s.

Now using kinemaics second equation.

S = Ut +at²/2.

225 = 20t +0.5t²/2.

t²+80t – 1000= 0.

Now solving aove equation.

t = 10.99s and -90.99s.

negative value is not possible so t = 10.99 s.

Ajinkya

8 Years ago

Do the same as he has done but in the place of 1000 there will be 900.

t^2+80t-900=0

t^2+90t-10t-900=0

t(t+90)-10(t+90)=0

t=-90 and t=10.

Here t=-90 is rejected so t=10 is the answer.

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two trains one of length 100m and another of length 125m are moving in mutually opposite directions along parallel lines, meet each other, each with speed 10m/s. if their acceleration are 0.3 m/s2 and 0.2m/s2 respectively then find the time taken to pass each other.

Kaushal Jain

2 Answers

Deepak Kumar

Ajinkya

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