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Two trains initially separated byba distance d. One train moves with velocity v1 and the othet with velocity v2,such that v1>v2.Now the train moving with velocity v1 applies a constant retardation `a`. Prove that the hap between the two trains should be d>{(v1-v2)^2}÷2a so that the trsins do not collide.

Arnab Das , 9 Years ago
Grade 11
anser 1 Answers
Vikas TU
For first train let the speed be v1 then after a constant accleration the eqn. of motion becomes,
(x+d) = v1*t + 0.5at^2...................(1)
For second train the eqn. would be,
x = v2*t.........(2)
solving both eqns. we get,
t = [(v1-v2) + root( -(v1-v2)^2 + 2ad)]/a
Now the roots term should be greater than eqial to zero according to its domain,
Hence,
2ad – (v1-v2)^2 greater than equal to zero.
solving we get,
d greater than (v1-v2)^2/2a
Hence Proved.
Last Activity: 9 Years ago
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