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Grade upto college level Electric Current

Two trains each of length 90m moving in opposite directions along parallel tracks when their speeds are 60 km/h and 40km/h. If their acceleratins are 0.3 m/s*s and 0.15 m/s*s respectively, find the time they take to pass each other.

a)8s b)4s c)2s d)6.17s

Profile image of Deepak Patra
12 Years agoGrade upto college level
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

To determine the time it takes for the two trains to pass each other, we need to consider their initial speeds, lengths, and the effect of their accelerations. Let's break this down step by step.

Understanding the Problem

We have two trains:

  • Train A: Length = 90 m, Speed = 60 km/h, Acceleration = 0.3 m/s²
  • Train B: Length = 90 m, Speed = 40 km/h, Acceleration = 0.15 m/s²

Since they are moving in opposite directions, we can add their speeds to find the relative speed when they pass each other.

Converting Speeds

First, let's convert the speeds from km/h to m/s:

  • Speed of Train A: 60 km/h = (60 * 1000 m) / (3600 s) = 16.67 m/s
  • Speed of Train B: 40 km/h = (40 * 1000 m) / (3600 s) = 11.11 m/s

Calculating Initial Relative Speed

The initial relative speed of the two trains is:

Relative Speed = Speed of Train A + Speed of Train B

Relative Speed = 16.67 m/s + 11.11 m/s = 27.78 m/s

Considering Acceleration

Next, we need to account for the accelerations of both trains. The distance they need to cover to completely pass each other is the sum of their lengths:

Total Distance = Length of Train A + Length of Train B

Total Distance = 90 m + 90 m = 180 m

Using Kinematic Equations

Since both trains are accelerating, we can use the kinematic equation for distance:

d = ut + (1/2)at²

Where:

  • d = distance
  • u = initial speed
  • a = acceleration
  • t = time

Setting Up the Equation

For Train A:

d_A = 16.67t + (1/2)(0.3)t²

For Train B:

d_B = 11.11t + (1/2)(0.15)t²

The total distance covered when they pass each other is:

180 = d_A + d_B

Substituting the distances:

180 = (16.67t + 11.11t) + (0.15t² + 0.15t²)

Combining terms gives:

180 = 27.78t + 0.225t²

Rearranging the Equation

This can be rearranged into a standard quadratic form:

0.225t² + 27.78t - 180 = 0

Solving the Quadratic Equation

Using the quadratic formula, t = [ -b ± √(b² - 4ac) ] / 2a, where:

  • a = 0.225
  • b = 27.78
  • c = -180

Calculating the discriminant:

b² - 4ac = (27.78)² - 4(0.225)(-180)

Calculating gives:

Discriminant = 771.0884 + 162 = 933.0884

Now, applying the quadratic formula:

t = [ -27.78 ± √933.0884 ] / (2 * 0.225)

Calculating the square root and solving for t gives us two potential solutions, but we only consider the positive value since time cannot be negative.

Final Calculation

After performing the calculations, we find:

t ≈ 6.17 seconds

Conclusion

Thus, the time taken for the two trains to completely pass each other is approximately 6.17 seconds. Therefore, the correct answer is option d) 6.17s.