Arjun Bakshi
Last Activity: 10 Years ago
let speed of bus be u km/hr.
and the time interval be T min.
distance travelled by cycle in T min =uT
relative velocity of the cycle wrt the bus coming from same side =u-20/60
uT/(u-1/3)=18
uT=18u-6 (1)
relative velocity of cycle wrt to bus coming from diff. side
uT/(u+1/3)=6
uT =6u+2 (2)
Dividing (1) by (2)
6u+2=18u-6
8=12u
u=2/3 km/min
=40 km/h
from(2)
2/3*T=6*2/3 +2
T=9min