Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Two rods each of mass m and length l are joined to form cross. Moment of inertia passing through centre and perpendicular to plane is- Ml 2 /12, Ml 2 /6, Ml 2 /3, Ml 2 /2

Two rods each of mass m and length l  are joined to form cross. Moment of inertia passing through centre and perpendicular to plane is- Ml2/12, Ml2/6, Ml2/3, Ml2/2
 

Grade:

3 Answers

shashi K Sharma
46 Points
7 years ago
Dear Student
 
The moment of inertia for each rod is I = ml2/12 , about the middle point and perpendicular to the plane thus making the sum total for two rods as 2I , i.e. ml2/6
Gagarin
13 Points
2 years ago
2x1/12 ml^2 sin^2 45 = ml2/12So moment of inertia of the cross about bisector is I = ml^2/12
Rishi Sharma
askIITians Faculty 646 Points
one year ago
Dear Student,
Please find below the solution to your problem.

The moment of inertia for each rod is I = ml2/12 , about the middle point and perpendicular to the plane thus making the sum total for two rods as 2I , i.e. ml2/6

Thanks and Regards

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free