Himanshu Rathour
Last Activity: 6 Years ago
OB=300
Let distance between p and q become 120 after t s.
And are at point C and D.
Now, because p and q are moving with equal speed hence, CDO will be a right angled triangle.
Distance covered in time t by p and q=12t
CO=240-12t
DO=300-12t
(300-12t)²=(240-12t)²+(120)²
18000=1440t
t=12.5s
Therefore after 12.5 s p is at 240-12*(12.5)
=90m from 0
q is at 300-(12*12.5)
=150 form O
Now q speed of q has become 15m/s
Time taken by q to reach point O
=150/15
=10s
Time taken by p to reach point O
=90/12
=7.5s
Hence p will reach first at point O