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Two particles of mass 'm' are tied at the ends of a light string of length '2a'. The whole system is kept on a frictionless horizontal surface with the string held tight so that each mass is at a distance 'a' from the center 'P' (as shown in the figure). Now, the mid-point of the string is pulled vertically upwards with a small but constant force 'F'. As a result, the particles move toward each other on the surface. What is the magnitude of acceleration when the separation between them becomes '2x'

Two particles of mass 'm' are tied at the ends of a light string of length '2a'. The whole system is kept on a frictionless horizontal surface with the string held tight so that each mass is at a distance 'a' from the center 'P' (as shown in the figure). Now, the mid-point of the string is pulled vertically upwards with a small but constant force 'F'. As a result, the particles move toward each other on the surface. What is the magnitude of acceleration when the separation between them becomes '2x' 

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Draw FBD then
2T sin θ = F
T cos θ = mA
 
2  tanθ = F/mA 
 
A = F/2m (x/sqrt (a2 – x2)
 
hope it helps
 
Regards
Arun

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