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`        Two particles of mass 'm' are tied at the ends of a light string of length '2a'. The whole system is kept on a frictionless horizontal surface with the string held tight so that each mass is at a distance 'a' from the center 'P' (as shown in the figure). Now, the mid-point of the string is pulled vertically upwards with a small but constant force 'F'. As a result, the particles move toward each other on the surface. What is the magnitude of acceleration when the separation between them becomes '2x' `
one year ago

Arun
23032 Points
```							Draw FBD then2T sin θ = FT cos θ = mA 2  tanθ = F/mA  A = F/2m (x/sqrt (a2 – x2) hope it helps RegardsArun
```
one year ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions