Grade 11Mechanics

Two particles of equal mass M,go round a circle of radius R under the action of mutual gravitational attraction.The speed of each particle is:

Spicer

8 Years agoGrade 11

1 Answer

Dhyaan

8 Years ago

As the two particles moving in circular motion the distance of separation is 2R. The gravitational force according to the Newton's law of gravitation is:

GM^2/(2R)^2=mv^2/R

Since mutual gravitational force is the only force providing centripetal acceleration

which implies V is= ( GM / 4 R)^1/2

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Two particles of equal mass M,go round a circle of radius R under the action of mutual gravitational attraction.The speed of each particle is:

Spicer

1 Answer

Dhyaan

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