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Two particles execute SHM with amplitudes A and 2A, respectively and angular frequencies ω and 2ω. At t=0 they start with some initial phase difference. At t=(2pi/3ω) they are in the same phase. Their initial phase difference is?(Multiple correct)\t​pi/32pi/3\t4pi/3\tpi

Sunny Dhondkar , 7 Years ago
Grade 11
anser 1 Answers
Saurabh Koranglekar

Last Activity: 4 Years ago

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