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Grade 12th passMechanics

Two particles each of mass m are moving in a circle of radius r with a speed v as shown in figure . The value of v is .Ans v= √G/r(M+m/4)

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Profile image of Ananya Anand
8 Years agoGrade 12th pass
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1 Answer

Profile image of Khimraj
ApprovedApproved Tutor Answer8 Years ago
At equilibrium condition,
mv2/r = GMm/r2 + Gmm/(2r)2
So,
v2 = GM/r + Gm/4r
So v = \sqrt{(G/r)(M + m/4)}
Hence option (2) is correct.
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