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Grade 12th passMechanics

Two particles are thrown horizontally in opposite direction fro same point from height H simultaneously with velocities 4m/s and 3m/s. Find time when their velocities are perpendicular

Profile image of Shravan Gautam
8 Years agoGrade 12th pass
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1 Answer

Profile image of Khimraj
8 Years ago
velocity of first particle is
v1 = 4\hat{i} – gt\hat{j}
and velocity of second particle is
v2 = -3\hat{i} -gt\hat{j}
whenv1 and v2 become perpendicular
v1.v2 = 0
so
-12 + g2t2 = 0
then t = \sqrt{12}/g
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