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`        Two particles A and B are projected simultaneously from thetwo towers of height 10 m and 20 m respectively. Particle A isprojected with an initial speed of 10√2 m/s at an angle of 45with horizontal, while particle B is projected horizontally withspeed 10 m/s. If they collide in air, what is the distance dbetween the towers?`
4 months ago

Khimraj
3008 Points
```							No they will not collide as vertical component is not same for both projectiles.
```
4 months ago
Khimraj
3008 Points
```							Vo1 = 10√2 Vo1y = Vo1x = 10√2*√2/2 = 10.0 m8sec Vo2x = 10m/sec if they meet, then : h1+Vo1y*t-4.9t^2 = h2-4.9t^2 10+10t = 20+4.9t^2-4.9t^2 10t = 10 t = 1 distance = (Vo1x+Vo2x)*t = (10+10)*1 = 20.0 m
```
4 months ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions