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Two particles A and B are located in xy plane with their coordination (0, 0) and (d,0) respectively. At time t=0 the particle A starts moving towards B with velocity V (a) =k (x+d)^1/2 m/s, whereas the particle B starts moving towards A with velocity V (b) =k (x)^1/2 if they meet each other after sometime , then find their positions from origin.
Two particles A and B are located in xy plane with their coordination (0, 0) and (d,0) respectively. At time t=0 the particle A starts moving towards B with velocity V (a) =k (x+d)^1/2 m/s, whereas the particle B starts moving towards A with velocity V (b) =k (x)^1/2 if they meet each other after sometime , then find their positions from origin.

```
10 months ago

Arun
25768 Points
```							A particle of mass m is moving in a circular path under the action of radially inward acting conservative force. The total energy of the particle 2
```
10 months ago
Vikas TU
14146 Points
```							Assuming B to be at rest, A will move with velocity  V(AB) ​in the direction  The distance between them will first decrease from A to C and then increase beyond C.Minimum distance between them is BC which is equal to 4/sqrt(2)and the time after which they are at closest distance is :t = AC/Vab = 1 second
```
9 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions