badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass

                        

Two particles A and B are located in xy plane with their coordination (0, 0) and (d,0) respectively. At time t=0 the particle A starts moving towards B with velocity V (a) =k (x+d)^1/2 m/s, whereas the particle B starts moving towards A with velocity V (b) =k (x)^1/2 if they meet each other after sometime , then find their positions from origin.

7 months ago

Answers : (2)

Arun
24742 Points
							
A particle of mass m is moving in a circular path under the action of radially inward acting conservative force. The total energy of the particle 
7 months ago
Vikas TU
12278 Points
							
Assuming B to be at rest, A will move with velocity  
V(AB) ​in the direction  The distance between them will first decrease from A to C and then increase beyond C.
Minimum distance between them is BC which is equal to 4/sqrt(2)
and the time after which they are at closest distance is :t = AC/Vab = 1 second
7 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details