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Two particles A and B are initially 40m apart. A is behind B. A is moving with uniform velocity of 10 m/s towards B . Particle B( at rest ) starts moving away from A with constant acceleration of 2 m/s^2.The time at which the minimum distance between the two occurs is- and the minimum distance between the two is-

Two particles A and B are initially 40m apart.  A is behind B. 
A is moving with uniform velocity of 10m/s towards B . Particle B(at rest) starts moving away from A with constant acceleration of 2m/s^2.The time at which the minimum distance between the two occurs is-
and the minimum distance between the two is-

Grade:12

1 Answers

Abhishek Kumar
askIITians Faculty 253 Points
6 years ago
For A,
x = 10t
For B,
x’ = 0.5 X 2 x t2

x’ – x = Distance between the two.
Differentiate it with respect to t to get the time at which minimum distance occurs.

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