Two particles A and B are initially 40m apart.A is behind B. A is moving with uniform velocity of 10m/s towards B . Particle B(at rest) starts moving away from A with constant acceleration of 2m/s^2.The time at which the minimum distance between the two occurs is-and the minimum distance between the two is-
R Achuthan , 9 Years ago
Grade 12
1 Answers
Abhishek Kumar
Last Activity: 9 Years ago
For A, x = 10t For B, x’ = 0.5 X 2 x t2
x’ – x = Distance between the two. Differentiate it with respect to t to get the time at which minimum distance occurs.
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