Two masses m1=1kg and m2 =2kg are connected by suspended by a weightless string by a massless pulley .assume that both the masses start from rest the distance travelled by the centre of mass in 2s is -a) 20/9m b) 40/9m c) 2/3 m d) 1/3 m

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siddharth swami · Answer

m 2 m 2 g- T = m 2 a T- m 1 g = m 1 a solving these equations we get, a= g/3 distance travelled by each block s= ut+ (1/2)at 2 = 20/3 m apllying centre of mass formula (m 2 *s – m 1 *s)/(m 2+ m 1 )= 20/9

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Two masses m1=1kg and m2 =2kg are connected by suspended by a weightless string by a massless pulley .assume that both the masses start from rest the distance travelled by the centre of mass in 2s is -a) 20/9m b) 40/9m c) 2/3 m d) 1/3 m

Two masses m1=1kg and m2 =2kg are connected by suspended by a weightless string by a massless pulley .assume that both the masses start from rest the distance travelled by the centre of mass in 2s is -a) 20/9m b) 40/9m c) 2/3 m d) 1/3 m

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Two masses m1=1kg and m2 =2kg are connected by suspended by a weightless string by a massless pulley .assume that both the masses start from rest the distance travelled by the centre of mass in 2s is -a) 20/9m b) 40/9m c) 2/3 m d) 1/3 m

Two masses m1=1kg and m2 =2kg are connected by suspended by a weightless string by a massless pulley .assume that both the masses start from rest the distance travelled by the centre of mass in 2s is -a) 20/9m b) 40/9m c) 2/3 m d) 1/3 m

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