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Two masses m1=1kg and m2 =2kg are connected by suspended by a weightless string by a massless pulley .assume that both the masses start from rest the distance travelled by the centre of mass in 2s is -a) 20/9m b) 40/9m c) 2/3 m d) 1/3 m
m2 m2g- T = m2 aT- m1g = m1asolving these equations we get, a= g/3distance travelled by each blocks= ut+ (1/2)at2 = 20/3 mapllying centre of mass formula(m2*s – m1*s)/(m2+m1)= 20/9
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