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`        Two masses m and M are attached with strings.for the system to be in equilibrium we have`
one year ago

Ashutosh Mohan Sharma
180 Points
```							We regard first M and m forming a single system. Then,applying Newton’s second law,we have(M+m) a=F ……………(1) Let F be applied on M. From free body diagram of M we have following equation.Ma=F-T………………….(2) Therefore,T=F-Ma .Substituting for a from Eq.(1),we get,T=F-M(F/M+m)=Fm/M+m…………(3).This tension is the force on m. Then, writing Eq. Of motion for m,ma=T=Fm/(M+m). But if we assume the force F applied on m then the tension will be T=FM/(M+m).
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions