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Grade 12Mechanics

Two identical solid copper spheres of radius R placed in contact with each other. The gravitational attracton between them is proportional to

Profile image of Isha
6 Years agoGrade 12
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1 Answer

Profile image of Arun
6 Years ago
F        =GM1M2/R^2
MASS = DESITY*VOLUME
 SO M1= D*(4/3 PI R^3)
        M2=D*(4/3 PI R^3) 
GIVEN RADIUS OF BOTH SPHERES "R" THEY ARE ATTACHED, SO TOTAL RADIUS IS "2R"
F          = {G(D*4/3 PI R^3)(D*4/3 PI R^3)}/(2R)^2    
F           = CONSTANT PART (R^6/4R^2)
F            = (CONSTANT PART/4)  (R^4)
F             = CONSTANT (R^4)
SO THAT ATTRACTION DEPENDS ON R^4