Two identical particles A and B are attached to a string of length 2l A to middle and B to one of the ends. The string is whirled in a horizontal circle , with the end o fixed . If the kinetic energy of B relative to A is E , then the absolute kinetic energies of A and B are E and 2E E and 4 EE and 3EE and 5E
Pp , 6 Years ago
Grade 11
1 Answers
Arun
Last Activity: 6 Years ago
Since A and B are rotating with the same angular velocity, The kinetic energies are Va = wl and Vb = 2wl
E = ½ m (Vb2 – Va2) = E
hence Ea =E
and Eb = 4E
hence option 2 is correct.
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