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`        Two identical metal spheres are released from the top of a tower after t seconds of each other such that they fall along the same vertical line. If the air resistance is neglected then at any instant of time during their fall,  `
one year ago

Vikas TU
9762 Points
```							Dear Student,At t = t (when the diference is t between both of them)For first ball,x1 = 0 + 0.5gt^2For second ball which it thrown after time t,x2 = 0 + 0*0 = 0  The difference of displacement would be => x1 – x2 = 0.5gt^2 Now say after time t’ ,x1 = 0 + 0.5g(t + t’)^2and x2 = 0 + 0.5gt^2Differnece would be => x1 – x2 = 0.5g(t + t’)^2 – 0.5gt^2 = 0.5g(t’)(2t + t’)Which is not the same.  For speed at time t for first ball and second ball,v1 = gtandv2 = 0and v1 – v2 = gtat time after t’v1 = 0 + g(t + t’)and v2 = 0 + gt’v1 – v2 = gt + gt’ – gt’ = gtwhich is the same.Hence the speed difference would be constant.b option.
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions