Abhishek
Last Activity: 9 Years ago
PE = mghcm=dAhgh/2=dAgh2/2 (taking base as reference)
so PE initial = dAg(h12+h22)/2
in final position h= (h1+h2)/2 height of centre of mass=(h1+h2)/4
mass=d(2A)((h1+h2)/2) =dA(h1+h2)
so PE final = mghcm=dAg(h1+h2)2 /4
change in pe = -work done by conservative force
work = -change in pe
= PE initial -PE final
= dAg(h12+h22-2h1h2)/4
=dAg(h1-h2)2/4