Flag Mechanics> two identical cylinderical vessels with b...
question mark

two identical cylinderical vessels with bases at the same level each contain a liquid of density d. the height of liquid in one vessel is h1 and that of other vessel is h2. the area of either base is A. the work done by gravity in equastising the levels when the two vessels are connected is ?

harsh , 9 Years ago
Grade
anser 1 Answers
Abhishek

Last Activity: 9 Years ago

PE = mghcm=dAhgh/2=dAgh2/2 (taking base as reference)
so PE initial = dAg(h12+h22)/2
    
in final position h= (h1+h2)/2         height of centre of mass=(h1+h2)/4
mass=d(2A)((h1+h2)/2) =dA(h1+h2)
so PE final = mghcm=dAg(h1+h2)2 /4
 
change in pe = -work done by conservative force
work = -change in pe
         = PE initial -PE final
         = dAg(h12+h22-2h1h2)/4
         =dAg(h1-h2)2/4

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...