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Two identical beads are attached to free springs of spring constant
k=[( 2 + √3)mg ] / √3 R.
Initially both springs make an angle of 60 at the fixed point and normal length of each spring is 2R where R is the radius of smooth ring over which bead is sliding. ring is placed on vertical plane and beads are at symmetry with respect to vertical line as diameter.
* Normal reaction on one of the bead at initial moment due to ring is......
A. mg/2
B.√3mg/2
C.mg
D.none

ABC , 7 Years ago
Grade 11
anser 3 Answers
Eshan
568-1195_123.png
Last Activity: 6 Years ago
Eshan
Apologies,

The following is the correct answer-
568-1348_123.png
Last Activity: 6 Years ago
KRISH RAY
This answer is wrong the correct answer is
N = mg
Proof is given below:-
N= k∆xcos30° + mgcos60°
N= k{2-√3} . √3/2 + mg/2
N= R(2+√3)mg(2-√3)/√3R . √3/2 + mg/2
N= (4-3)mg/2 + mg/2
N= mg
 
Last Activity: 4 Years ago
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