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Two highways intersect, as shown in Fig. At the instant shown, a police car P is 41 m from the intersection and moving at 76 km/h. Motorist M is 57 m from the intersection and moving at 62 km/h. At this moment, what is the velocity (magnitude and angle with the line of sight) of the motorist with respect to the police car? Two highways intersect, as shown in Fig. At the instant shown, a police car P is 41 m from the intersection and moving at 76 km/h. Motorist M is 57 m from the intersection and moving at 62 km/h. At this moment, what is the velocity (magnitude and angle with the line of sight) of the motorist with respect to the police car?
Assume that the unit vector points in the positive x direction and the unit vector points in the positive y direction as shown in figure above.The velocity of the Police car with respect to ground is:The negative sign highlights the fact that the police car moves in a direction opposite to that of unit vector .Similarly, the velocity of the motorcyclist with respect to ground is:The negative sign highlights the fact that the motorcyclist moves in a direction opposite to that of unit vector .The velocity of the motorcyclist with respect to police car is given as:Round off to two significant figures,Therefore, the magnitude of velocity of motorcyclist with respect to police car is 98 km/h .Round off to two significant figures,θ = - 39°Here, L is the separation between the motorcyclist and the intersection point whereas H is the separation between the police car and intersection point (refer figure).Round off to two significant figures,
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