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Two forces equal to p and 2p act on particle when the first force is increased by 120N and the second force is doubled the direction of the resultant remains the same find the value of p?

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4 years ago

Vikas TU
14146 Points
```							for first two forces,Resultant1 = root(p^2 + 4p^2 + 4p^2 *costhetha).......................(1)after increasing forces,Resultant2 = root( (p+120)^2  + (4p)^2 + 2*4p*(p+120)costhetha).................(2)and the direcn. is same therefore,tanthetha = p/Resultant1...............(3)and tanthetha = (p+120)/Resualtant2.................(4)solve the four eqns.and get the values of R1 R2 thetha and p.
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions