Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Two boys enter a running escalator at the ground floor of a shopping mall. The first boy repeatedly follows a cycle of p1 step up and then q1  steps down whereas the second boy repeatedly follows a cycle of p2  steps up and then q2  step down. Both of them move relative to escalator with a speed vr. If the boys take t1 and t2 respectively to reach the first floor in complete numbers of cycles, how fast is the escalator running?SEE IMAGE for answer`
4 months ago

Arun
22572 Points
```							Dear student I have solved question by taking p1 = 1, q2 = 2p2 = 2, q1 = 1Vr = 50t1 = 250t2 = 50 Let the speed of escalator be x.speed*time=displacementand displacement covered by both of them is from ground floor to first floortherefore,(50-x)250=(50+x)50.12500-250x=2500+50x-200x=-10000x=(50cm/s)/2.=25cm/sec
```
4 months ago
pra
14 Points
```							Why I usep2 = 2, q1 = 1Vr = 50t1 = 250t2 = 50????????????????????????????????????????????????????
```
4 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions