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Two boys enter a running escalator at the ground floor of a shopping mall. The first boy repeatedly follows a cycle of p 1 step up and then q 1 steps down whereas the second boy repeatedly follows a cycle of p 2 steps up and then q 2 step down. Both of them move relative to escalator with a speed v r . If the boys take t 1 and t 2 respectively to reach the first floor in complete numbers of cycles, how fast is the escalator running? SEE IMAGE for answer

Two boys enter a running escalator at the ground floor of a shopping mall. The first boy repeatedly follows a cycle of p1 step up and then q1  steps down whereas the second boy repeatedly follows a cycle of p2  steps up and then q2  step down. Both of them move relative to escalator with a speed vr. If the boys take t1 and t2 respectively to reach the first floor in complete numbers of cycles, how fast is the escalator running?
SEE IMAGE for answer

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Grade:11

2 Answers

Arun
25750 Points
4 years ago
Dear student
 
I have solved question by taking p1 = 1, q2 = 2
p2 = 2, q1 = 1
Vr = 50
t1 = 250
t2 = 50
 

Let the speed of escalator be x.

speed*time=displacement

and displacement covered by both of them is from ground floor to first floor

therefore,

(50-x)250=(50+x)50.

12500-250x=2500+50x

-200x=-10000

x=(50cm/s)/2.

=25cm/sec

pra
14 Points
4 years ago
Why I use
p2 = 2, q1 = 1
Vr = 50
t1 = 250
t2 = 50
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