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Grade: 11
        
Two boys enter a running escalator at the ground floor of a shopping mall. The first boy repeatedly follows a cycle of p1 step up and then q1  steps down whereas the second boy repeatedly follows a cycle of p steps up and then q2  step down. Both of them move relative to escalator with a speed vr. If the boys take t1 and trespectively to reach the first floor in complete numbers of cycles, how fast is the escalator running?
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4 months ago

Answers : (2)

Arun
22572 Points
							
Dear student
 
I have solved question by taking p1 = 1, q2 = 2
p2 = 2, q1 = 1
Vr = 50
t1 = 250
t2 = 50
 

Let the speed of escalator be x.

speed*time=displacement

and displacement covered by both of them is from ground floor to first floor

therefore,

(50-x)250=(50+x)50.

12500-250x=2500+50x

-200x=-10000

x=(50cm/s)/2.

=25cm/sec

4 months ago
pra
14 Points
							
Why I use
p2 = 2, q1 = 1
Vr = 50
t1 = 250
t2 = 50
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4 months ago
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