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        Two bodies of masses 2 kg and 3 kg are connected by a metal wire of cross section 0.04 mm2. Breaking stress of metal wire is 2.5 GPa. Find the maximum force that can be applied to the mass 3 kg so that the string does not break.
3 years ago

npcyh
26 Points
							let F be the force applied on 3 kg mass. then F-T=3a (T is the tension in the string and a is acceleration of blocks). and T=2a i.e., a=T/2. putting in above equation F-T=3T/2. i.e., F=5T/2. now maximum stress is T/A=2.5*10^9. so,T=(2.5*10^9)(0.04*10^-6)=100N. so, maximum force=5*100/2=250N. see if i have done any calculation mistake but this is the process

3 years ago
eswar
13 Points
							Two bodies of masses 1 kg and 2 kg are connected by a metal wire shown in figure. A force of 10 N is applied on the body of mass 2 kg. the breaking stress of metal wire is 2 \times {10^9}N{m^{ - 2}}2−mN901×22×10​9​​Nm​−2​​what should be minimum radius of the wire used, if it is not to break?

3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

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