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Grade 11Mechanics

Two bodies of mass m and 4m are attached with string as shown In the figure. The body of mass m hanging from a string of length I is executing oscillations of angular amplitude theta while the other body is at rest. The minimum coefficient of friction between the mass 4 m and the horizontal surface should be

Profile image of Sri ADITYA Deevi
9 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

To determine the minimum coefficient of friction required to keep the mass 4m stationary while the mass m oscillates, we need to analyze the forces acting on both masses during the oscillation. This involves understanding the dynamics of the system, particularly the forces at play when the mass m reaches its maximum angular displacement.

Understanding the Forces Involved

When the mass m oscillates, it experiences a gravitational force acting downwards and a tension force in the string. The mass 4m, which is resting on a horizontal surface, will experience a frictional force that opposes any tendency to move due to the oscillation of mass m.

Key Forces Acting on Mass m

  • Gravitational Force (Weight): The weight of mass m is given by W = mg, where g is the acceleration due to gravity.
  • Tension in the String: As mass m swings, the tension in the string changes depending on its position.
  • Centripetal Force: When mass m reaches its maximum displacement, it has a component of centripetal force that acts horizontally, which can affect mass 4m.

Analyzing the Oscillation

At the maximum angular displacement (theta), the forces acting on mass m can be resolved into components. The tension in the string must counteract both the gravitational force and provide the necessary centripetal force for circular motion. The horizontal component of the tension will exert a force on mass 4m.

Calculating the Required Friction

Let’s denote the angle of displacement as θ. The horizontal component of the tension T when mass m is at its maximum displacement can be expressed as:

T_horizontal = T * sin(θ)

At this point, the frictional force (F_friction) acting on mass 4m must be equal to or greater than the horizontal component of the tension to prevent mass 4m from moving. The frictional force can be calculated using:

F_friction = μ * N

where μ is the coefficient of friction and N is the normal force. For mass 4m resting on a horizontal surface, the normal force is equal to its weight:

N = 4mg

Setting Up the Equation

To keep mass 4m stationary, we set the frictional force equal to the horizontal component of the tension:

μ * (4mg) = T * sin(θ)

Now, we need to express T in terms of m and g. At the maximum displacement, the tension can be approximated as:

T = mg + (mv^2)/L

where v is the velocity of mass m at the lowest point of the swing, and L is the length of the string. The velocity can be derived from energy conservation principles or kinematics, but for simplicity, we can assume that T is primarily influenced by the weight of mass m when it is at rest.

Finding the Minimum Coefficient of Friction

Substituting T into our friction equation gives:

μ * (4mg) = (mg + (mv^2)/L) * sin(θ)

From this equation, we can isolate μ:

μ = [(mg + (mv^2)/L) * sin(θ)] / (4mg)

To find the minimum coefficient of friction, we need to consider the maximum value of sin(θ), which is 1 when θ is 90 degrees. Thus, we can simplify our equation further:

μ_min = [(mg + (mv^2)/L)] / (4mg)

As you can see, the minimum coefficient of friction depends on the velocity of mass m and the length of the string. If we assume that the oscillation is small, we can use small angle approximations to simplify our calculations further.

Conclusion

In summary, the minimum coefficient of friction required to keep mass 4m stationary while mass m oscillates can be derived from the balance of forces acting on both masses. By analyzing the forces and applying the principles of dynamics, we can determine the necessary conditions for equilibrium in this system.