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mass of 'A' is Ma
mass of 'B' is Mb
both of them undergo an accelaration of 'g' as it is falling from a height
initial velocity of both is zero as it is dropped from rest.
From 2nd equation of motion.
S = 1/2 a t2 [ since u = 0 , it is not taken. ]
a = 1/2g t12
b = 1/2g t22
a/b = t12 / t22
t1 / t2 = √a/b
this the the ratio of times taken by Ma and Mb
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