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two bodies are thrown from same point with the same velocity of 50m/s . if their angles of projection are complementary to each other and the difference of maximum heights is 30m,the minimum and maximum heights are? 50m and 80m 47.5m and 77.5 m 30m and 60m 25m and 55 m
let the angle made with horizontal by 1st body is theta.so, the angle made with horizontal by 2nd body is (90 - theta).h1 + h2 = u2sin2theta/2g + u2sin2(90-theta)/2g = u2sin2theta/2g + u2cos2theta/2g = u2/2g (sin2theta+cos2theta) = u2/2g = 50 * 50 / 2*10 = 125......(1)h1-h2 = 30........(2)subtacting (2) from (1),h2 = 47.5 and h1= 77.5
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