Two bodies are connected with a spring and one of the particles is given a velocity v find 1* maximum velocity of second particle and 2* max. extension in the spring. Answer fast please!

when velocity is given to one body the that time the amplitude of oscillations will be maximum compression in the spring . At the time of maximum compression, velocities of both the bodies will be equal say V₁. and this velocity be the velocity of the second body at the of release after compression. so by law of conservation of momentum ---
m₁*v = (m₁+m₂)V² if the mass of bodies is m1 and m2
so V₁ = (m₁*v) / (m₁+m₂) ------------------------------------(i)
by the conservation of energy
1/2m1*v² = 1/2kx²+1/2(m1+m2)V₁² ----------------------(ii)
where k is the spring constant and x is the max compression. after the release this will be the max. extension.......
by solving (i) and (ii)
x= [m₁m₂v²/k(m₁+m₂)]^1/2