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Two blocks of masses 5 kg and 2 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 7m/s to the heavier block in the direction of the lighter block.The velocity of the centre of mass is what???
Velocity of centre of massVcm = [m1v1 + m2v2] / [m1+m2] = [(5x7) + (2x0)] / [5+2] = 5 = 5 m/sec Hope it helps
Vcm = [m1v1 + m2v2] / [m1+m2]
= [(5x7) + (2x0)] / [5+2]
= 5
= 5 m/sec
Hope it helps
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