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Grade: 11

                        

Two blocks of masses 4 kg and 0.1 kg are connected by a massless string that passes over a frictionless pulley find out the minimum height from where the smaller block must be released so that bigger block just lifts up?? (solve using the concept of impulse)

2 years ago

Answers : (1)

Heman
13 Points
							
From energy conservation - 1/2mv=mgh
                       ;;;//.              V=√2gh......(1)
                                  F=dp/dt == impulse on 0.1 kg is =0.1×√2gh= 40dt ......(2)
 
Assume that dt is 1sec  and g=10 m=.1kg so solve this equation 2 answer is h=8km
29 days ago
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