Two blocks of masses 4 kg and 0.1 kg are connected by a massless string that passes over a frictionless pulley find out the minimum height from where the smaller block must be released so that bigger block just lifts up?? (solve using the concept of impulse)

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Heman · Answer

From energy conservation - 1/2mv 2 =mgh ;;;//. V=√2gh......(1) F=dp/dt == impulse on 0.1 kg is =0.1×√2gh= 40dt ......(2) Assume that dt is 1sec and g=10 m=.1kg so solve this equation 2 answer is h=8km

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Two blocks of masses 4 kg and 0.1 kg are connected by a massless string that passes over a frictionless pulley find out the minimum height from where the smaller block must be released so that bigger block just lifts up?? (solve using the concept of impulse)

Two blocks of masses 4 kg and 0.1 kg are connected by a massless string that passes over a frictionless pulley find out the minimum height from where the smaller block must be released so that bigger block just lifts up?? (solve using the concept of impulse)

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Two blocks of masses 4 kg and 0.1 kg are connected by a massless string that passes over a frictionless pulley find out the minimum height from where the smaller block must be released so that bigger block just lifts up?? (solve using the concept of impulse)

Two blocks of masses 4 kg and 0.1 kg are connected by a massless string that passes over a frictionless pulley find out the minimum height from where the smaller block must be released so that bigger block just lifts up?? (solve using the concept of impulse)

1 Answers

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