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Two blocks of masses 4 kg and 0.1 kg are connected by a massless string that passes over a frictionless pulley find out the minimum height from where the smaller block must be released so that bigger block just lifts up?? (solve using the concept of impulse)

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2 years ago

Heman
13 Points
```							From energy conservation - 1/2mv2 =mgh                       ;;;//.              V=√2gh......(1)                                  F=dp/dt == impulse on 0.1 kg is =0.1×√2gh= 40dt ......(2) Assume that dt is 1sec  and g=10 m=.1kg so solve this equation 2 answer is h=8km
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29 days ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions