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Grade: 11

                        

Two blocks of masses 10kg and 4kg are connected by a spring of negligible mass and placed on a friction less horizontal surface. An impulse gives a velocity of 14m/s to the heavier block in the direction of the lighter block. The velocity of the centre of mass is:A)30m/s B)20m/s C)10m/s D)5m/s

3 years ago

Answers : (1)

Shreyas
19 Points
							
Here the lighter box is initaly at rest . When an impulse is given to heavier box the box moves ahead
So, 
V1=14m/s
V2=om/s
m1=10kg
m2=4kg
So V=m1v1+m2v2/m1+m2
        =10*14+0/14
        =10m/s
 
3 years ago
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