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```
Two blocks of masses 10kg and 4kg are connected by a spring of negligible mass and placed on a friction less horizontal surface. An impulse gives a velocity of 14m/s to the heavier block in the direction of the lighter block. The velocity of the centre of mass is:A)30m/s B)20m/s C)10m/s D)5m/s

```
3 years ago

Shreyas
19 Points
```							Here the lighter box is initaly at rest . When an impulse is given to heavier box the box moves aheadSo, V1=14m/sV2=om/sm1=10kgm2=4kgSo V=m1v1+m2v2/m1+m2        =10*14+0/14        =10m/s
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions