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`        two blocks A and Bof masses 2kg and 3kg are connceted by a light string and placed on a horizontal surface if coefficient of friction for all surfaces os 0.1 and g=10 then the acceleration of the system is ? when the applied F=45 `
one year ago

Kush
9 Points
```							m1 be the mass on the table, m2 be the hanging mass, g be the acceleration due to gravity, I be the moment of inertia of the pulley, w be the angular speed of the pulley. Equating initial PE of m2 to final KE of the whole system plus work done against friction: m2 gh = (m1 + m2)v^2 / 2 + Iw^2 / 2 + u m1 gh ...(1) v = rw Eliminating w from (1): 2(m2 - u m1)gh = v^2[ m1 + m2 + I / r^2 ] I can't tell from the question which way round the masses are. Is som further explanation or a diagram missing? If m1 = 2kg and m2 = 3kg: v = sqrt{ 2(3.0 - 0.30 * 2.0)9.81 * 0.6 / [ 2.0 + 3.0 + 0.004 / 0.05^2 ] } = 2.07 m/s. If m1 = 3kg and m2 = 2kg: v = sqrt{ 2(2.0 - 0.30 * 3.0)9.81 * 0.6 / [ 3.0 + 2.0 + 0.004 / 0.05^2 ] = 1.40 m/s.
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions