0

Guest

Courses New

Two blocks A and B of mass 6kg and 3kg respectively are placed on a smooth surface of an elevator in such a way that B is placed above A.The coefficient of friction between the two blocks is 1/4 and the elevator is ascending up with acceleration g/3.A horizontal force 10N is applied on A. Find the accelerations of the blocks w.r.t. the elevator.

Two blocks A and B of mass 6kg and
3kg respectively are placed on a
smooth surface of an
elevator in such a way that B is
placed above A.The coefficient of
friction between the two
blocks is 1/4 and the elevator is
ascending up with acceleration
g/3.A horizontal force 10N
is applied on A. Find the
accelerations of the blocks w.r.t. the
elevator.

Grade:12th pass

1 Answers

Arpit Kumar
31 Points
10 years ago
Since,the elevator is acc upwards the value of normal will change. N-mg=mg/3 N=4mg/3=4*3*9.8/3=39.2N This is the normal force between the blocks. Now check wether the blocks will slip or not. The common acc between the two blocks is 10/3+6=10/9m/s2 Force required by B to move with common acc in horizontal direction=3*10/9=10/3N Limiting friction=coefficient of friction*normal reaction=1/4*39.2=9.8N Since,9.8 is greater than 10/3,the blocks will not slip. So, the common acc of the blocks with respect to the elevator will be equal to10/9m/s2 Along the x-axis

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More