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Two blocks A and B of mass 6kg and3kg respectively are placed on asmooth surface of anelevator in such a way that B isplaced above A.The coefficient offriction between the twoblocks is 1/4 and the elevator isascending up with accelerationg/3.A horizontal force 10Nis applied on A. Find theaccelerations of the blocks w.r.t. theelevator.
Since,the elevator is acc upwards the value of normal will change. N-mg=mg/3 N=4mg/3=4*3*9.8/3=39.2N This is the normal force between the blocks. Now check wether the blocks will slip or not. The common acc between the two blocks is 10/3+6=10/9m/s2 Force required by B to move with common acc in horizontal direction=3*10/9=10/3N Limiting friction=coefficient of friction*normal reaction=1/4*39.2=9.8N Since,9.8 is greater than 10/3,the blocks will not slip. So, the common acc of the blocks with respect to the elevator will be equal to10/9m/s2 Along the x-axis
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