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Grade: 12th pass
        Two blocks A and B of mass 6kg and
3kg respectively are placed on a
smooth surface of an
elevator in such a way that B is
placed above A.The coefficient of
friction between the two
blocks is 1/4 and the elevator is
ascending up with acceleration
g/3.A horizontal force 10N
is applied on A. Find the
accelerations of the blocks w.r.t. the
elevator.
6 years ago

Answers : (1)

Arpit Kumar
31 Points
							Since,the elevator is acc upwards the value of normal will change.
N-mg=mg/3
N=4mg/3=4*3*9.8/3=39.2N
This is the normal force between the blocks.
Now check wether the blocks will slip or not.
The common acc between the two blocks is 10/3+6=10/9m/s2
Force required by B to move with common acc in horizontal direction=3*10/9=10/3N
Limiting friction=coefficient of friction*normal reaction=1/4*39.2=9.8N
Since,9.8 is greater than 10/3,the blocks will not slip.
So, the common acc of the blocks with respect to the elevator will be equal to10/9m/s2 Along the x-axis
						
6 years ago
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