First draw the diagram by yourself according to the the given conditions and draw FBD.
Mass of A= 6Kg, Mass of B= 3Kg  
As elevator is accelerating upwards with acceleration of g/3,value of Normal Reaction(N) will change
N-Mg=Mg/3
N=4Mg/3
Hence value of  N between 2 blocks will be = 4*3*9.8/3= 39.2Newton
Now common acceleration of 2 blocks in horizontal direction = 10/(3+6) =10/9 m/s2

*Now check whether there will be slipping between 2 blocks or not
Force required by B to move with common acceleration in horizontal direction = 3*10/9 = 10/3 Newton
Maximum friction between blocks = µ*N = 1/4*39.2 = 9.8 Newton
As 9.8>10/3,
There will be no slipping between the blocks.
They will move with common acceleration in horizontal direction that is 10/9 m/s2


Hence acceleration of both blocks w.r.t. the elevator is = (10/9 i cap + g/3 j cap) m/s2....
						

							Sorry my final answer is w.r.t Earth.

Hence acceleration of both blocks w.r.t. the elevator is = (10/9 i cap ) m/s2....
						

							Is it 3g or 3kg.....