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Two blocks A and B of equal mass m are connected through a massless string and arranged as shown ,friction is absent everywhere .When the system is released from rest then find tension in string and acceleration of A.
Two blocks A and B of equal mass m are connected through a massless string and arranged as shown ,friction is absent everywhere .When the system is released from rest then find tension in string and acceleration of A.

```
2 years ago

Manan B Patel
13 Points
```							For block A,ma = mgsin30 + TT=m(a-g/2)  -----------1 Now, For block B,ma = mg - Tma = mg - ma + mg/22ma = 3mg/2a = 3g/4 Now, putting value of a in eq. 1T = m(3g/4-g/2)T = mg/4
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions