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Two blocks A and B of equal mass m are connected through a massless string and arranged as shown ,friction is absent everywhere .When the system is released from rest then find tension in string and acceleration of A.
For block A,ma = mgsin30 + TT=m(a-g/2) -----------1 Now, For block B,ma = mg - Tma = mg - ma + mg/22ma = 3mg/2a = 3g/4 Now, putting value of a in eq. 1T = m(3g/4-g/2)T = mg/4
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