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`        Two blocks A(3 kg ) and B(6kg) are connected by a spring stiffness 512N/m and placed on smooth horizontal surface. Initially the spring has equilibrium length. Velocity 1.8m/s and 2.2m/s are imparted to A and B in opposite direction. The maximum extension of the spring will be______cm`
2 years ago

Karan Gupta
51 Points
```							At maximum extension of the spring, velocities of both blocks will be same. Conservation of momentum:6*2.2 – 3*1.8 = (3+6)*VV = 0.867 m/s Conservation of energy:1/2*3*1.8*1.8 + 1/2*6*2.2*2.2 = 1/2*(6+3)*0.867*0.867 + 1/2*512* X*XX = 0.25 m = 25 cm
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions